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Result:
Calculate Log Base 2 of 1
To solve the equation log 2 (1) = x carry out the following steps.- Apply the change of base rule: log a (x) = log b (x) / log b (a) With b = 10: log a (x) = log(x) / log(a)
- Substitute the variables: With x = 1, a = 2: log 2 (1) = log(1) / log(2)
- Evaluate the term: log(1) / log(2) = 1.39794000867204 / 1.92427928606188 = 0 = Logarithm of 1 with base 2
Additional Information
- From the definition of logarithm b y = x ⇔ y = log b(x) follows that 2 0 = 1
- 2 0 = 1 is the exponential form of log2 (1)
- 2 is the logarithm base of log2 (1)
- 1 is the argument of log2 (1)
- 0 is the exponent or power of 2 0 = 1
Frequently searched terms on our site include:
FAQs
What is the value of log2 1?
Log2 (1) = 0.
How do you find the value of log 21?
Carry out the change of base logarithm operation.
What does log 2 1 mean?
It means the logarithm of 1 with base 2.
How do you solve log base 2 1?
Apply the change of base rule, substitute the variables, and evaluate the term.
What is the log base 2 of 1?
The value is 0.
How do you write log 2 1 in exponential form?
In exponential form is 2 0 = 1.
What is log2 (1) equal to?
log base 2 of 1 = 0.
For further questions about the logarithm equation, common logarithms, the exponential function or the exponential equation fill in the form at the bottom.
Summary
In conclusion, log base 2 of 1 = 0.You now know everything about the logarithm with base 2, argument 1 and exponent 0.
Further information, particularly about the binary logarithm, natural logarithm and decadic logarithm can be located in our article logarithm.
Besides the types of logarithms, there, we also shed a light on the terms on the properties of logarithms and the logarithm function, just to name a few.
Thanks for visiting Log2 (1).
Table
Our quick conversion table is easy to use:| log 2(x) | Value | |
|---|---|---|
| log 2(0.5) | = | -1 |
| log 2(0.51) | = | -0.97143084780323 |
| log 2(0.52) | = | -0.94341647163363 |
| log 2(0.53) | = | -0.91593573521153 |
| log 2(0.54) | = | -0.88896868761126 |
| log 2(0.55) | = | -0.86249647625006 |
| log 2(0.56) | = | -0.83650126771712 |
| log 2(0.57) | = | -0.81096617560998 |
| log 2(0.58) | = | -0.78587519464715 |
| log 2(0.59) | = | -0.76121314041288 |
| log 2(0.6) | = | -0.73696559416621 |
| log 2(0.61) | = | -0.71311885221184 |
| log 2(0.62) | = | -0.68965987938785 |
| log 2(0.63) | = | -0.66657626627481 |
| log 2(0.64) | = | -0.64385618977472 |
| log 2(0.65) | = | -0.62148837674627 |
| log 2(0.66) | = | -0.59946207041627 |
| log 2(0.67) | = | -0.57776699931695 |
| log 2(0.68) | = | -0.55639334852438 |
| log 2(0.69) | = | -0.53533173299656 |
| log 2(0.7) | = | -0.51457317282976 |
| log 2(0.71) | = | -0.49410907027004 |
| log 2(0.72) | = | -0.47393118833241 |
| log 2(0.73) | = | -0.45403163089471 |
| log 2(0.74) | = | -0.43440282414577 |
| log 2(0.75) | = | -0.41503749927884 |
| log 2(0.76) | = | -0.39592867633114 |
| log 2(0.77) | = | -0.37706964907982 |
| log 2(0.78) | = | -0.35845397091248 |
| log 2(0.79) | = | -0.34007544159762 |
| log 2(0.8) | = | -0.32192809488736 |
| log 2(0.81) | = | -0.3040061868901 |
| log 2(0.82) | = | -0.28630418515664 |
| log 2(0.83) | = | -0.2688167584278 |
| log 2(0.84) | = | -0.25153876699596 |
| log 2(0.85) | = | -0.23446525363702 |
| log 2(0.86) | = | -0.21759143507263 |
| log 2(0.87) | = | -0.200912693926 |
| log 2(0.88) | = | -0.18442457113743 |
| log 2(0.89) | = | -0.16812275880833 |
| log 2(0.9) | = | -0.15200309344505 |
| log 2(0.91) | = | -0.13606154957603 |
| log 2(0.92) | = | -0.12029423371771 |
| log 2(0.93) | = | -0.10469737866669 |
| log 2(0.94) | = | -0.089267338097087 |
| log 2(0.95) | = | -0.074000581443776 |
| log 2(0.96) | = | -0.058893689053568 |
| log 2(0.97) | = | -0.043943347587596 |
| log 2(0.98) | = | -0.029146345659516 |
| log 2(0.99) | = | -0.014499569695114 |
| log 2(1) | = | 6.4068530076298E-16 |
| log 2(1.01) | = | 0.014355292977071 |
| log 2(1.02) | = | 0.028569152196772 |
| log 2(1.03) | = | 0.042644337408494 |
| log 2(1.04) | = | 0.056583528366368 |
| log 2(1.05) | = | 0.070389327891399 |
| log 2(1.06) | = | 0.084064264788475 |
| log 2(1.07) | = | 0.097610796626423 |
| log 2(1.08) | = | 0.11103131238874 |
| log 2(1.09) | = | 0.1243281350022 |
| log 2(1.1) | = | 0.13750352374994 |
| log 2(1.11) | = | 0.15055967657538 |
| log 2(1.12) | = | 0.16349873228288 |
| log 2(1.13) | = | 0.17632277264046 |
| log 2(1.14) | = | 0.18903382439002 |
| log 2(1.15) | = | 0.20163386116965 |
| log 2(1.16) | = | 0.21412480535285 |
| log 2(1.17) | = | 0.22650852980868 |
| log 2(1.18) | = | 0.23878685958712 |
| log 2(1.19) | = | 0.25096157353322 |
| log 2(1.2) | = | 0.26303440583379 |
| log 2(1.21) | = | 0.27500704749987 |
| log 2(1.22) | = | 0.28688114778816 |
| log 2(1.23) | = | 0.29865831556452 |
| log 2(1.24) | = | 0.31034012061215 |
| log 2(1.25) | = | 0.32192809488736 |
| log 2(1.26) | = | 0.33342373372519 |
| log 2(1.27) | = | 0.34482849699744 |
| log 2(1.28) | = | 0.35614381022528 |
| log 2(1.29) | = | 0.36737106564853 |
| log 2(1.3) | = | 0.37851162325373 |
| log 2(1.31) | = | 0.38956681176273 |
| log 2(1.32) | = | 0.40053792958373 |
| log 2(1.33) | = | 0.41142624572647 |
| log 2(1.34) | = | 0.42223300068305 |
| log 2(1.35) | = | 0.43295940727611 |
| log 2(1.36) | = | 0.44360665147562 |
| log 2(1.37) | = | 0.4541758931858 |
| log 2(1.38) | = | 0.46466826700345 |
| log 2(1.39) | = | 0.47508488294878 |
| log 2(1.4) | = | 0.48542682717024 |
| log 2(1.41) | = | 0.49569516262407 |
| log 2(1.42) | = | 0.50589092972996 |
| log 2(1.43) | = | 0.51601514700367 |
| log 2(1.44) | = | 0.52606881166759 |
| log 2(1.45) | = | 0.53605290024021 |
| log 2(1.46) | = | 0.54596836910529 |
| log 2(1.47) | = | 0.55581615506164 |
| log 2(1.48) | = | 0.56559717585423 |
| log 2(1.49) | = | 0.57531233068744 |
| log 2(1.5) | = | 0.58496250072116 |
Base 2 Logarithm Quiz
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