Welcome to Logarithm.app. On this site you can find everything about logarithms.

Every inverse function f −1(x) is a function that undoes another function f(x).

It essentially means that if an input x of the function f(x) produces y as output, then the input y of the inverse function f −1(x) produces the output x. And vice versa!

Logarithm are the inverse functions to exponentiations.




This log calculator (logarithm calculator) allows you to calculate the logarithm of a (positive real) number with a chosen base (positive, not equal to 1). Regardless of whether you are looking for a natural logarithm, log base 2, log base 10 (decimal logarithm), or log base any number, this calculator will solve your problem.

How to use calculator:
Please provide any two values to calculate the logarithm, based on the logarithm equation logb(x)=y. It can accept e as a base input.
If you want to calculate the decimal logarithm of a number x; log (x), then base b should be 10.
If you want to calculate the logarithm of a number x to the base b; logb (x), then base b should be the base number.
If you want to calculate the natural logarithm of a number x; ln(x), then base b should be e.

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Logarithm Definition

b y = x ⇔ y = log b(x)

b, x, y ∈ R +, b ≠ 1

R + denotes the set of positive real numbers.

Logarithm Parts

b is the base
x is the argument
y is the exponent

Logarithm Examples

Logarithmic Form Exponential form
log 2(8) = 3 2 3 = 8
log 10(1000) = 3 10 3 = 1000
ln(x) = 1 e 0 = 1
log 3(9) = 2 3 3 = 9
log(100) = 2 10 2 = 100

ln(x) is the natural logarithm which uses the number e as base. You may think of it as log e(x).

The logarithm with base 2 is called binary logarithm, and the logarithm with base 10 is usually called decimal logarithm.

The decimal logarithm, which is also known as common logarithm and decadic logarithm, often has it’s base omitted:

log 10(x) = log(x)

The graph below depicts ln(x), log 2(x) as well as log(x) for small values of x.

Evaluating Logarithms

1. Assumed you want to solve this equation:

log 10(1000000) = y.

Write it in the equivalent form:

10 y = 1000000

Take the log with base 10 from both sides:

log 1010 y = log 10(1000000)

y = 6

2. Supposed you want to solve:

log 2(32) = y.

Write it in the equivalent form:

2 y = 32

Take the log with base 2 from both sides:

log 22 y = log 2(32)

y = 5

Practice makes experts, so you may soon find yourself skipping the procedure and evaluating a log just by asking, “b to what power is y”?

3. Try solving log 4(64) by asking yourself “4 to what power is 64?”


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